-2x^2+23x-60=0

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Solution for -2x^2+23x-60=0 equation:



-2x^2+23x-60=0
a = -2; b = 23; c = -60;
Δ = b2-4ac
Δ = 232-4·(-2)·(-60)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-7}{2*-2}=\frac{-30}{-4} =7+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+7}{2*-2}=\frac{-16}{-4} =+4 $

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